(2x+y)(3x^2+2xy+5y^2)=

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Solution for (2x+y)(3x^2+2xy+5y^2)= equation: 


Simplifying
(2x + y)(3x2 + 2xy + 5y2) = 0

Reorder the terms:
(2x + y)(2xy + 3x2 + 5y2) = 0

Multiply (2x + y) * (2xy + 3x2 + 5y2)
(2x * (2xy + 3x2 + 5y2) + y(2xy + 3x2 + 5y2)) = 0
((2xy * 2x + 3x2 * 2x + 5y2 * 2x) + y(2xy + 3x2 + 5y2)) = 0

Reorder the terms:
((10xy2 + 4x2y + 6x3) + y(2xy + 3x2 + 5y2)) = 0
((10xy2 + 4x2y + 6x3) + y(2xy + 3x2 + 5y2)) = 0
(10xy2 + 4x2y + 6x3 + (2xy * y + 3x2 * y + 5y2 * y)) = 0
(10xy2 + 4x2y + 6x3 + (2xy2 + 3x2y + 5y3)) = 0

Reorder the terms:
(10xy2 + 2xy2 + 4x2y + 3x2y + 6x3 + 5y3) = 0

Combine like terms: 10xy2 + 2xy2 = 12xy2
(12xy2 + 4x2y + 3x2y + 6x3 + 5y3) = 0

Combine like terms: 4x2y + 3x2y = 7x2y
(12xy2 + 7x2y + 6x3 + 5y3) = 0

Solving
12xy2 + 7x2y + 6x3 + 5y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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